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Q.

Let a computer program generate only the digits 0 and 1 to form a string of binary numbers with probability of occurrence of 0 at even places be  12and probability of occurrence of 0at the odd place be 13. Then the probability that '10' is followed by '01' is equal to:

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a

13

b

16

c

19

d

118

answer is C.

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Detailed Solution

Probability of getting 1 in even places is 12 and the probability of getting 1 in the odd places is 23 Case (1)  Even  Odd  Even  Odd  0110 12231213 Case (2) 13122312Case 2 is the case of reverse to the case (1)The probability is  =12×23×12×13+13×12×23×12=19
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