Let conditions C1 and C2 be defined as follows: C1:b2−4ac≥0,C2:a,−b,c are of same sign. The roots of ax2+bx+c=0are real and positive, if
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a
both C1 and C2 are satisfied
b
only C2 is satisfied
c
only C1 is satisfied
d
None of these
answer is A.
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Detailed Solution
C1:b2−4ac≥0C2:a,−b,c are of same sign ax2+bx+c=0 has real roots. Then D≥0 i.e., C1 must be satisfied. (i) Let a,−b,c>0 Then −b2a>0 (ii) Let a,−b,c<0 Then −b2a>0 Hence, for roots to be +ve,C2 must be satisfied. Thus, both C1,C2 are satisfied.