Let cos2θ+b and sin2θ+b are roots of the equation x2+4x+6116=0. The equation whose roots are tan2θ and cot2θ is
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a
x2−14x+1=0
b
x2−4x+1=0
c
x2−10x+1=0
d
None of these
answer is A.
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Detailed Solution
cos2θ+b+sin2θ+b=−4⇒b=−52cos2θ+bsin2θ+b=6116⇒ cos2θsin2θ+b+b2=6116⇒ cos2θsin2θ=6116+52−254=6116−154=116 Sum of roots =tan2θ+cot2θ=1−2sin2θcos2θsin2θcos2θ=1−18116=14Product of roots = 1