Let the curve C be the mirror image of the parabola y2=4x with respect to the line x+y+4=0. If A and B are the points of intersection of C with the line y=−5, then the distance between A and B is

Mirror image of the parabola y2=4x with respect to the line x+y+4=0is  C≡ (-x-4)2=-4(y+4)⇒(x+4)2=-4(y+4)→(1)Given y=-5→(2) Substituting 2 in 1, we get(x+4)2=4x+4=±2∴ points of intersection of  (1)&(2) areA=(-2,-5)B(-6,-5)⇒AB=4