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Q.

Let d1, and d2 be the lengths of the perpendiculars drawn from the foci S and S' of the ellipse x2a2+y2b2=1 to the tangent at any point P on the ellipse.   Then, SP : S'P =

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a

d1:d2

b

d2:d1

c

d12:d22

d

d1:d2

answer is A.

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Detailed Solution

Tangent at P(acos⁡α,bsin⁡α) is xacos⁡α+ybsin⁡α=1The distance of focus s(ae,0) from this tangent isd1=|ecos⁡α−1|cos2⁡αa2+sin2⁡αb2=1−ecos⁡αcos2⁡αa2+sin2⁡αb2' *u distance of focus s'(-ae, 0) from this line is d2=1+ecos⁡αcos2⁡αa2+sin2⁡αb2or  d1d2=1−ecos⁡α1+ecos⁡αNow, SP=a−aecos⁡α and S′P=a+aecos⁡αor  SPS'P=1−ecos⁡α1+ecos⁡α=d1d2
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