Let d1, and d2 be the lengths of the perpendiculars drawn from the foci S and S' of the ellipse x2a2+y2b2=1 to the tangent at any point P on the ellipse. Then, SP : S'P =
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a
d1:d2
b
d2:d1
c
d12:d22
d
d1:d2
answer is A.
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Detailed Solution
Tangent at P(acosα,bsinα) is xacosα+ybsinα=1The distance of focus s(ae,0) from this tangent isd1=|ecosα−1|cos2αa2+sin2αb2=1−ecosαcos2αa2+sin2αb2' *u distance of focus s'(-ae, 0) from this line is d2=1+ecosαcos2αa2+sin2αb2or d1d2=1−ecosα1+ecosαNow, SP=a−aecosα and S′P=a+aecosαor SPS'P=1−ecosα1+ecosα=d1d2