Let a determinant be given by A=a b cp q rx y z and suppose that det. A=6 If B=p+x q+y r+za+x b+y c+za+p b+q c+r then det(B) is
We have B=p+x q+y r+za+x b+y c+za+p b+q c+r
Apply R1→R1+R2+R3, we get
B=2a+p+xb+q+yc+r+za+xb+yc+za+pb+qc+r
Apply R2→R2−R1 and R3→R3−R1, we get
=2a+p+xb+q+yc+r+z−p−q−r−x−y−z
Apply R1→R1+R2+R3
∴ det. B=2(6)=12