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Q.

Let a = 1 1 1 ….1 (55 digits), b=1 +102+....+104,c=1+105+1010+1015+....+1050 then

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a

a = b + c

b

a = bc

c

b = ac

d

c = ab

answer is B.

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Detailed Solution

a=1+10+102+….+1054=1055−110−1=1055−1105−1×105−110−1=bc
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