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 Let E be an event which is neither a certainty nor an impos-  sibility. If probability is such that P(E)=1+λ+λ2 and 

PE=(1+λ)2 in terms of an unknown λ. Then P(E) is =

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a
1
b
34
c
14
d
None of these

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detailed solution

Correct option is B

P(E)+PE′=1=1+λ+λ2+(1+λ)2or  2λ2+3λ+1=0or  (2λ+1)(λ+1)=0or  λ=−1,−12Then, P(E)=1+(−1)+(−1)2=1 (not possible) =1+−12+−122=12+14=34


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