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a
PEC+PFC
b
PEC−PFC
c
PEC−P(F)
d
P(E)−PFC
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Correct option is C
We have,E∩F∩G=ϕPEc∩Fc/G =PEc∩Fc∩GP(G) =P(G)−P(E∩G)−P(G∩F)P(G) [From Venn diagram Ec∩Fc∩G=G−E∩G−F∩G=P(G)−P(E)P(G)−P(G)P(F)P(G) ["' E' F' G are pairwise independent]=1−P(E)−P(F)=PEc−P(F)Similar Questions
A couple has 3 children and it is known that atleast one of them is a boy. Then the probability that the couple will have exactly two boys is
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