Q.

Let E1 and E2 be two ellipses whose centers are at the origin. The major axes of   E1 and E2  lie along the x-axis and the y-axis, respectively. Let S be the circle x2+y−12=2. The straight line x+y=3 touches the curves S,  E1 and E2 at P, Q and R, respectively. Suppose that PQ=PR=223. If  e1and  e2are the eccentricities of   E1 and E2   respectively, then the correct expression(s) is (are)

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a

e12+e22=4340

b

e1e2=7210

c

e12−e22=58

d

e1e2=34

answer is A.

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Detailed Solution

The line x+y=3 touches the circle x2+y−12=2 at PP is foot of perpendicular from 0,1 to x+y=3⇒ P1,2Since PQ=223=PR  we have Q1+2232, 2−2232E1:x2a2+y2b2=1 with e12=a2−b2a2 ∴  a2+b2=9  x+y=3  touches  E1⇒a2m2+b2=c2Since Q lies on E1, we have 259a2+169b2=1⇒ a2=5, b2=4∴e12=15 similarly R1−23,  2+23 lies on x2c2+y2d2=1   c
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Let E1 and E2 be two ellipses whose centers are at the origin. The major axes of   E1 and E2  lie along the x-axis and the y-axis, respectively. Let S be the circle x2+y−12=2. The straight line x+y=3 touches the curves S,  E1 and E2 at P, Q and R, respectively. Suppose that PQ=PR=223. If  e1and  e2are the eccentricities of   E1 and E2   respectively, then the correct expression(s) is (are)