First slide
Types of real valued functions XI
Question

Let E=[13+150]+[13+250]++ up to 50 terms, then

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Solution

For, 1x33,13<13+x50<1 therefore,

[13+x50]=0for1x33

For 34x50,1<13+x50<43

[13+x50]=1 for 34x50

Thus E=17

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