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Let E=13+150+13+250+13+350++ up to 50 terms, then the exponent of 2 in E! is

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a
17
b
25
c
15
d
None of these

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detailed solution

Correct option is C

Let, E=13+x50 where x = 1,2, ... ,50 For, 1≤x≤33,13<13+x50<1∴ 13+x50=0, for 1≤x≤33For 34≤x≤50, 1<13+x50<43⇒13+x50=1 , For 34≤x≤50Thus, E=17 and p=2∵24<17<25∴a=4Exponent of 2 in (17)!=172+174+178+1716                                   =8+4+2+1=15


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The number 24 ! is divisible by


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