Q.

Let E1=X∈ℝ:x≠1 and xx−1>0 and E2=X∈ℝ1:sin−1logexx−1is a real number  (Here, the inverse trigonometric function sin−1x assumes values in−π2,π2.Let f:E1→ℝ be function defined by fx=logexx−1  and  g:E2→ℝ be the function defined by g(x)=sin−1(logxx−1.)            LIST-I                                                             LIST-II            P. The range of f is                                     1. −∞,11−e∪ee−1,∞           Q. The range of g contains                             2. (0, 1)            R. The domain of f contains                           3.. −12,12             S. The domain of g is                                   4.−∞,0∪0,∞                                                                                     5. −∞,ee−1                                                                                     6. −∞,0∪12,ee−1

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a

P-3;Q-3;R-6;S-5

b

P-4;Q-2;R-1;S-6

c

P-4;Q-3;R-6;S-5

d

P-4;Q-2;R-1;S-1

answer is D.

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Detailed Solution

E1:xx-1>0⇒xx-1>0⇒E1: :x∈(-∞,0)∪(1,∞)E2:-1≤lnxx+1≤11e≤xx-1≤e Now xx-1-1e≥0⇒(e-1)x+1e(x-1)≥0e-1x+1≥0e-1x≥-1x≤11-eand xx-1-e≤0 x-ex+ex-1≤0 x1-e+ex-1≤0 x1-e≤-e x≥ee-1Therefore, E2:-∞,11-e∪ee-1,∞
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