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Q.

Let f:[12 , 1]→[−1 , 1] is given by f(x)=3x−4x3 then f−1(x) is given by

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a

sin[13sin−1x]

b

3cos(sin−1x)

c

3sin−1(sinx)

d

sin(13cos−1x)

answer is A.

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Detailed Solution

put x=sinθ⇒θ=sin−1x y=f(x)=sin3θ θ=13(sin−1y) f−1(x)=sin(13sin−1x)

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