Let ‘f’ be a continuity function on [1,3]. If ‘f’ takes only rational values for ‘x’ and f(2)=10 then f(1.5)=

f is continuous on [1,  3] Given f(x) can takes only  Rational values ∀xGiven f(2)=10if f(x) takes any rational number other than 10 say ‘n’ then it should take the irrational values between 10 and n which contradicts the statement. hence⇒f(x) is constant function, f(x)=10,∀x∈[1,3]⇒f(1.5)=10