First slide
Evaluation of definite integrals
Question

Let f be a continuous function satisfying πt2f(x)+x2dx=π+43t3 for all t, then fπ2/4 is equal to

Moderate
Solution

Differentiating both sides, we have

ft2+t42t=4t2ft2+t4=2t ft2=2tt4

so fπ24=fπ22=2π2π24

=ππ416.

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