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Questions  

Let f : [4, ∞) → [4, ∞) be a function defined by, f (x) = 5x(x – 4), then f –1 (x) is

a
2−4+log5⁡x
b
2+4+log5⁡x
c
15x(x−4)
d
None of these

detailed solution

Correct option is B

Let y = 5x(x–4) ⇒ x (x – 4) = log5 y⇒x2−4x−log5⁡y=0⇒x=4±16+4log5⁡y2 =2±4+log5⁡y But x≥4, so x=2+4+log5⁡y∴f−1(y)=2+4+log5⁡y

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