Let f : (4, 6) → (6, 8) be a function defined by f(x)=x+x2 (where [ ⋅ ] denotes the greatest integer function), then f – 1 (x) is equal to
x−x2
– x – 2
x – 2
1x+x2
Since f : (4, 6) → (6, 8),∴ f (x) = x + 2∴ f-1x = x – 2