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Let f : (4, 6) → (6, 8) be a function defined by $f (x) = x + [\frac{x}{2}]$ (where [ ⋅ ] denotes the greatest integer function), then f ^{– 1}(x) is equal to

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x−x2

– x – 2

x – 2

1x+x2

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detailed solution

Correct option is C

Since f : (4, 6) → (6, 8),∴ f (x) = x + 2∴ f-1x = x – 2

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Let f : (4, 6) → (6, 8) be a function defined by f(x)=x+x2 (where [ ⋅ ] denotes the greatest integer function), then f – 1 (x) is equal to

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Let f : (4, 6) → (6, 8) be a function defined by $f (x) = x + [\frac{x}{2}]$ (where [ ⋅ ] denotes the greatest integer function), then f ^{– 1}(x) is equal to