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Q.

Let f : (4, 6) → (6, 8) be a function defined by f(x)=x+x2 (where [ ⋅ ] denotes the greatest integer function), then f – 1 (x) is equal to

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a

x−x2

b

– x – 2

c

x – 2

d

1x+x2

answer is C.

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Detailed Solution

Since f : (4, 6) → (6, 8),∴ f (x) = x + 2∴ f-1x = x – 2
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