First slide
Algebra of real valued functions
Question

Let f : {(1,1), (2,3), (0,-1), (-1,-3)} be a function from z to z defined by f(x) = ax+b, for some integers a, b then (a, b) =

Moderate
Solution

fx=ax+b f1=1a+b=1 f2=32a+b=3 solving a=2 b=-1

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App