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Let f : {(1,1), (2,3), (0,-1), (-1,-3)} be a function from z to z defined by f(x) = ax+b, for some integers a, b then (a, b) =

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a

(-1,2)

b

(2,-1)

c

(3,-2)

d

(0,3)

answer is B.

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Detailed Solution

fx=ax+b f1=1⇒a+b=1 f2=3⇒2a+b=3 solving a=2 b=-1

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