Let ‘f’ be an injective function with domain {x, y, z} and range {1,2,3} such that exactly one of the following statements is correct and the remaining are false f(x) = 1. f(x)=1, f(y)≠1, f(z)≠2 the value of f−1(1) is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
x
b
y
c
z
d
x or z
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Suppose f(x) = 1, then f(y)≠1, f(z)=2⇒f is not an injection.Suppose f(y)≠1, thenf(z)=2, f(y)=3, f(x)≠1 A contradictionSuppose f(z)≠2, thenf(y)=1, f(z) = 3, f(x) = 2 this is true ∴ f−1(1)=y