Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Let ‘f’ be an injective function with domain {x, y, z} and range {1,2,3} such that exactly one of the following statements is correct and the remaining are false f(x) = 1. f(x)=1, f(y)≠1, f(z)≠2 the value of f−1(1) is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

x

b

y

c

z

d

x or z

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Suppose f(x) = 1, then f(y)≠1, f(z)=2⇒f is not an injection.Suppose f(y)≠1, thenf(z)=2, f(y)=3, f(x)≠1 A contradictionSuppose f(z)≠2, thenf(y)=1, f(z) = 3, f(x) = 2 this is true  ∴ f−1(1)=y
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon