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Q.

Let f be an invertible function from R→R satisfying the equation f3x−x3+2f2x+2x3+1fx−x3=0 Then the value of f'(8)×f−1'(8), is :

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a

12

b

16

c

20

d

32

answer is B.

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Detailed Solution

(f(x)−1)2f(x)−x3=0f(x)=x3f′(x)=3x2
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