First slide
Functions (XII)
Question

 Let f be an invertible function from RR satisfying the equation f3xx3+2f2x+2x3+1fxx3=0

 Then the value of f'(8)×f1'(8), is : 

Moderate
Solution

(f(x)1)2f(x)x3=0f(x)=x3f(x)=3x2

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