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Questions  

Let f(θ)=cosθcos2θcos4θcos7θ , then f(π/15) is equal to 

a
14
b
18
c
116
d
132

detailed solution

Correct option is C

f(θ)=12sin⁡θ(2sin⁡θcos⁡θ)cos⁡2θcos⁡4θcos⁡7θ=12×2sin⁡θ(2sin⁡2θcos⁡2θ)cos⁡4θcos⁡7θ=12×4sin⁡θ(2sin⁡4θcos⁡4θ)cos⁡7θ=12×8sin⁡θ[2sin⁡8θcos⁡7θ]=116sin⁡θ[sin⁡(15θ)+sin⁡θ]when θ=π15,f(θ)=116

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