Let f(2)=4 and f′(2)=4 Then, limx→2 xf(2)−2f(x)x−2 is given by
2
-2
-4
3
We have,
lim x→2 xf(2)−2f(x)x−2=limx→2 xf(2)−2f(2)+2f(2)−2f(x)x−2=limx→2 (x−2)f(2)x−2−2limx→2 f(x)−f(2)x−2=f(2)−2f′(2)=4−2×4=−4