Let f, g and h be continuous functions on [0, a] such that f(x)=f(a−x),g(x)=−g(a−x) and 3h(x)−4h(a−x)=5. Then ∫0a f(x)g(x)h(x)dx
is equal to
5/4
3/4
1
none of these
I=∫0a f(x)g(x)h(x)dx=∫0a f(a−x)g(a−x)h(a−x)dx=∫0a f(x){−g(x)}34h(x)−54dx74I=54∫0a f(x)g(x)dx⇒I=57I1
where I1=∫0a f(x)g(x)dx
=∫0a f(a−x)g(a−x)dx=∫0a f(x)[−g(x)]dx=−I1⇒2I1=0⇒I1=0
Thus, I = 0.