Let fn(θ)=cosθ2+cos2θ+cos7θ2+…+cos(3n−2)θ2sinθ2+sin2θ+sin7θ2+…+sin(3n−2)θ2 then
f33π16=2−1
f5π28=2+1
f7π60=(2+3)
none of these
We have fn(θ)=cot(3n−1)θ4
∴ f33π16=cot8×14×3π16=cot3π8=2−1f5π28=cot14×14×π28=cotπ8=2+1f7π60=cot20×14×π60=cotπ12=(2+3)