Questions
Let , then
a
nf(n)−1
b
(n+1)f(n)−n
c
(n+1)f(n)+n
d
nf(n)+n
detailed solution
Correct option is B
We have f(n)=1+12+13+…+1n∴ f(1)+f(2)+…+f(n)=1+1+12+1+12+13+…+1+12+13+…+1n=n+(n−1)2+(n−2)3+…+n−(n−1)n=n1+12+13+…+1n−12+23+…+n−1n=n1+12+13+…+1n−1−12+1−13+…+1−1n=n1+12+13+…+1n−(n−1)−12+13+…+1n=nf(n)−{(n−1)−(f(n)−1)}=(n+1)f(n)−nTalk to our academic expert!
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