Questions
a
f(4)=f(5)
b
f(8)=f(9)
c
f(7)=f(8)
d
f(5)=f(6)
detailed solution
Correct option is C
f(1+f(1))=4f(1)⇒ f(1+4)=4×4⇒ f(5)=16 Now f(5+f(5))=4f(5)⇒ f(5+16)=4×16⇒f(21)=64Talk to our academic expert!
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be an even function for all Then the sum of all possible values of a is (where [.] and {.} denote greatest integer function and fractional part function, respectively)
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