Let f:[−2,2]→R be defined by f(x)=−1,−2≤x<0x−1,0≤x≤2. Then sum of the roots of the equation f(|x|)=x is
-1
0
-12
1
|x|∈[0,2]∴ f(|x|)=|x|−1=x⇒ x=−12