Let f:(0,∞)→R and let
F(x)=∫0x f(t)dt
If Fx2=x2(1+x) then f (4) equals
54
7
4
2
F(x)=∫0x f(t)dt⇒F′(x)=f(x)∴f(4)=F′(2)
Also, 2xF′x2=2x(1+x)+x2⇒F′x2=1+3x/2
∴f(4)=F′22=1+3=4