First slide
Evaluation of definite integrals
Question

Let  f:(0,)R and let

F(x)=0xf(t)dt

If Fx2=x2(1+x) then f (4) equals

Moderate
Solution

F(x)=0xf(t)dtF(x)=f(x)f(4)=F(2)

 Also, 2xFx2=2x(1+x)+x2Fx2=1+3x/2

f(4)=F22=1+3=4

 

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