Let f:R→Rbe a function defined by f(x+1)=f(x)−5f(x)−3∀x∈R. Then which of the following statement(s) is/are true ?
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a
f(2008)=f(2004)
b
f(2006)=f(2010)
c
f(2006)=f(2002)
d
f(2006)=f(2018)
answer is A.
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Detailed Solution
f(x+1)=f(x)−5f(x)−3 (1)or f(x)f(x+1)−3f(x+1)=f(x)−5or f(x)=3f(x+1)−5f(x+1)−1Replacing x by (x - 1), we getf(x−1)=3f(x)−5f(x)−1 (2)Using(1), f(x+2)=f(x+1)−5f(x+1)−3=f(x)−5f(x)−3−5f(x)−5f(x)−3−3=2f(x)−5f(x)−2 (3)Using (2), f(x−2)=3f(x−1)−5f(x−1)−1=33f(x)−5f(x)−1−53f(x)−5f(x)−1−1 =2f(x)−5f(x)−2 (4)Using (3) and (4), we have f (x + 2) = f (x - 2).Therefore f(x+4)=f(x), i.e., f(x) is periodic with period 4.