Let f : R → R be a function defined by, f(x)=x+x2,then f is

We have, f(x)=x+x2=x+|x|Clearly, f is not one-one as f (– 1) = f (– 2) = 0 but – 1 ≠ –2.Also, f is not onto as f (x) ≥ 0 ∀ x ∈ R,∴ range of f = (0, ∞) ⊂ R.