Let f : R → R be a function defined by, $$f(x)=x+x2$$,then f is

Correct option is 4None of these

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Let f : R → R be a function defined by, $f (x) = x + \sqrt{x^{2}}, then f is$

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Correct option is D

We have, f(x)=x+x2=x+|x|Clearly, f is not one-one as f (– 1) = f (– 2) = 0 but – 1 ≠ –2.Also, f is not onto as f (x) ≥ 0 ∀ x ∈ R,∴ range of f = (0, ∞) ⊂ R.

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Let f : R → R be a function defined by, f(x)=x+x2,then f is

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Let f : R → R be a function defined by, $f (x) = x + \sqrt{x^{2}}, then f is$