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Q.

Let f:R→R be such that for all x∈R, 21+x+21-x, f(x)  and  3x+3-x are in A.P.   Then the  minimum value of f(x) is:

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a

2

b

3

c

4

d

0

answer is B.

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Detailed Solution

f(x)=21-x+21+x+3x+3-x2=2x+12x+123x+13x≥2+1⇒f(x)≥3
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Let f:R→R be such that for all x∈R, 21+x+21-x, f(x)  and  3x+3-x are in A.P.   Then the  minimum value of f(x) is: