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Questions  

Let f(θ)=sinθsin3θsin5θ , then f(π/14) is equal to

a
1/8
b
1/4
c
1/7
d
1/14

detailed solution

Correct option is A

As π14−π2−3π7,3π14−π2−2π7 and 5π14=π2−π7 , we can write   fπ14=cos⁡3π7cos⁡2π7cos⁡π7⇒ 2sin⁡π7fπ14=sin⁡2π7cos⁡2π7cos⁡3π7⇒ 4sin⁡π7fπ14=sin⁡4π7cos⁡3π7⇒ 8sin⁡π7fπ14=sin⁡7π7+sin⁡π7=sin⁡π7⇒ fπ14=18

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