First slide
Functions (XII)
Question

let f(θ)=sin2θcos2θ1+4sin4θsin2θ1+cos2θ4sin4θ1+sin2θcos2θ4sin4θ then f is 

Moderate
Solution

f(θ)=1011101+sin2θcos2θ4sin2θ

                                              (R1R1-R3   R2 R2-R3)

=0011101+sin2θcos2θ4sin4θ+4sin4θ   (C1 C1 + C3)

=cos2θ+1+sin2θ+4sin4θ

-2(1+2sin 4 θ)

which is periodic function with period 2π4=π2.

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