First slide
Introduction to limits
Question

Let f(θ)=1tan9θ(1+tanθ)10+(2+tanθ)10++(20+tanθ)1020tanθ The left hand limit of f(θ) as θπ2 is

Moderate
Solution

Let x=tanθ. Then

ftan1x=(1+x)10+(2+x)10++(20+x)1020x10x9

and x as θπ2

 limθπ2f(θ)=limxftan1x=limx(1+x)10+(2+x)10++(20+x)1020x10x9=limxr=120(r+x)10x10x9=limxr=120 10C0r10+10C1r9x++10C9r9x9=r=120limx10C0r10+ 10C1r9x8++10C9r=r=11010C9r=10r=120r=10×20×212=2100

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App