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Questions  

Letf(x)=[a]25[a]+4x36{a}25{a}+1x(tanx)×sgnx be an even function for all xR . Then the sum of 

 all possible values of a is (where [ ] and {} denote greatest  integer function and fractional part function, respectively) 

a
176
b
566
c
313
d
353

detailed solution

Correct option is D

fx=αx3-βx-tanx· Sgnx ,  where α=a 2-5a+4 ,β = 6a2-5a+1 since f is even function ⇒f-x=fx ⇒ -αx3+βx-tanx ·Sgnx=αx3-βx-tanx ·Sgnx ⇒ 2αx3-βx=0 for all x ∈R⇒α =0 and β=0   Identity in x therefore a2-5a+4=0  and 6a2-5a+1=0 ⇒          a=1 or a =4    and  a=13 or 12     ⇒  a = 1+13 ,1+12,4+13,4+12 ⇒  sum of the values of a =353

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