Let f(x)=absin x+b1−a2cos x+c, where |a|<1, b > 0 then
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a
maximum value of f(x) is b if c = 0
b
difference of maximum and minimum values of f(x) is 2b
c
f(x)=c if x=−cos−1 a
d
f(x)=c if x=cos−1 a
answer is A.
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Detailed Solution
f(x)=absinx+b1−a2cosx+c, where |a|<1,b<0f(x)=a2b2+b2−b2a2sin(x+α)+c =bsin(x+α)+c, where tanα=b1−a2ab=1−a2a =bcos(x−α)+c, where tanα=abb1−a2=a1−a2f(x)max−f(x)min=c+b−(c−b)=2bf(x)=c if x+α=0or x=−αor x=−cos−1 a