Let f′(x) be continuous at x=0 and f′′(0)=4. The value of limx→02f(x)−3f(2x)+f(4x)x2
2
11
12
None of these
limx→02f(x)−3f(2x)+f(4x)x2Form 00=limx→02f'(x)−6f'(2x)+4f'(4x)2xForm 00=limx→02f''x−12f"2x+16f"4x=f"0−6f"0+gf"0=3f"0=3×4=12
Hence (3)is the correct answer.