First slide
Differentiability
Question

 Let f(x) be continuous at x=0 and f′′(0)=4. The value of limx02f(x)3f(2x)+f(4x)x2

Moderate
Solution

limx02f(x)3f(2x)+f(4x)x2Form00=limx02f'(x)6f'(2x)+4f'(4x)2xForm00=limx02f''x12f"2x+16f"4x=f"06f"0+gf"0=3f"0=3×4=12

Hence (3)is the correct answer.

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