Let f(x) be defined for all x>0 and be continuous. Let f(x) satisfies fxy=f(x)−f(y) for all x,y and f(e)= 1. Then
f(x) is bounded
f1x→0 as x→0
xf(x)→1 as x→0
f(x)=logex
f(x) is continuous for all x>0 and
fxy=f(x)−f(y)
Also, f(e)=1
Therefore, clearly, f(x)=logex satisfies all these properties.
Thus, f(x)=logex, which is an unbounded function.