Let f(x) be the derivative of tan-1xx2+1+1 for all x∈R&g(x)=1f(x)+1fx2; for all x∈R. Let h-1(x) represent inverse function of h(x) then, which of the following is (are) TRUE?
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a
g(x) is an even function
b
Range of g(x) is [4,∞)
c
(g−1)'(8)=112
d
(g−1)'(8)=−112
answer is A.
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Detailed Solution
f(x)=ddxtan−1xx2+1+1 Let x=tanθ⇒θ∈−π2,π2tan−1tanθsecθ+1=tan−1tanθ2⇒θ2=tan−1x2⇒f(x)=121+x2g(x)=1f(x)+1fx2=21+x2+21+x4=2x4+x2+2 Range _:[4,∞) Since g is many one g−1 does not exists.