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Let f(x) be a differentiable function at x=a with f'(a)=2 and f(a)=4 . Then limx→axf(a)-af(x)x-a

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a

2a+4

b

2a-4

c

a+4

d

4−2a

answer is D.

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Detailed Solution

Ltx→ax·f(a)-a·f(x)x-a=Ltf(a)-a·f'(x)1 (Using L ' Hospital's rule) =f(a)-af'(a)=4-2a

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