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Let f(x) be a function satisfying f(x)=f(x) and 

f(0)=2Then  f(x)3+4f(x)dx 

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a
(1/4)log⁡3+8ex+C
b
(1/2)log⁡3+5ex+C
c
(1/4)log⁡3+4e2x+C
d
none of these

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detailed solution

Correct option is A

First show that  f(x)=2ex. Now, I=∫2ex3+8exdx=14log⁡3+8ex+C


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