Let F(x) be the primitive of 3x+2x−9w.r.t. x. If F(10)=60,  then the value of F(13) is

F(x)=∫3x+2x−9dx Let          x−9=t2⇒    dx=2t   dt ∴                                 F(x)=∫(3(t2+9)+2t.2t)dt =2∫(29+3t2)dt=2[29t+t3] F(x)=2[29x−9+(x−9)3/2]+C Given, F(10)=60=2[29+1]+C⇒C=0 ∴                 F(x)=2[29x−9+(x−9)3/2] F(13)=2[29×2+4×2]=132