First slide
Introduction to Determinants
Question

Let f(x)=2cos2xsin2xsinxsin2x2sin2xcosxsinxcosx0. Then the value of 0π/2f(x)+f'(x)dx is

Moderate
Solution

Applying C1C12sinxC3 and C2C2+2cosxC3, we get

f(x)=20sinx02cosxsinxcosx0=2cos2x+2sin2x=2

 f'(x)=0

 0π/2f(x)+f'(x)=dx=0π/22dx=π

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