Let f(x)=ex, g(x)=3x−2 be two functions from R→R . The domain of the function (gof)−1 is
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a
(2,∞)
b
R+
c
(−2,∞)
d
None
answer is C.
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Detailed Solution
f(x)=ex, g(x)=3x−2 , then f:R→R+, g:R→R ∴ gof: R→R is defined and given by(gof)(x)=g(f(x))=g(ex)=3ex−2 Clearly, gof is one-one but not ontoWhen x→−∞, 3ex−2→−2 x→∞, 3ex−2→+∞ and ex is increasing function∴ Range gof=(−2,∞) ∴ gof=R→(−2,∞) is one-one onto⇒ Domain (gof)−1=(−2,∞) .