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Questions  

 Let f(x)=ex12nsinnxalog1+xan for x016n for x=0and f is a continuous at x=0 then the value of a is 

a
16
b
2
c
8
d
4

detailed solution

Correct option is D

Ltx=0  fx=Ltx=0  ex−1x2nxansinnxa×xanlog1+xan.a2n=a2n=f0∴a2n=16n⇒a=4

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