First slide
Continuity
Question

 Let f(x)=ex12nsinnxalog1+xan for x016n for x=0and f is a continuous at x=0 then the value of a is 

Moderate
Solution

Ltx=0  fx=Ltx=0  ex1x2nxansinnxa×xanlog1+xan.a2n=a2n=f0

a2n=16na=4

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