Let f(x)=limn→∞ x2n−1x2n+1 Then
f(x)=1,|x|>1 −1,|x| <1
f(x)=1,|x|<1−1,|x|>1
f(x) is not defined for any value of x
f(x)=1 for |x|=1
We have,
limn→∞ x2n=0, if |x|<11, if |x|=1∞, if |x|>1∴ f(x)=limn→∞ 1−1x2n1+1x2n=limn→∞ −1,|x|<10,|x|=11,|x|>1