First slide
Evaluation of definite integrals
Question

 Let f(x)= maximum {x+|x|,x[x]}, where [x] is the greatest integer less than or equal to  x. Then 22f(x)dx=

Moderate
Solution

22f(x)dx=20{x}dx+022xdx=2×12×1×1+(40)=1+4=5

 

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