Let f(x) is a quadratic expression with positive integral coefficients such that for every α,β∈R, β>α and ∫αβ f(x)dx>0. Let g(t)=f"(t)⋅f(t) and g(0)=12. If the number of quadratics are ab where a and b are natural number then a+b2 is equal to (where ab is 2 digit number)
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Detailed Solution
Let f(x)=ax2+bx+c, ∵∫αβ f(x)dx>0 ∀α,β∈R a,b,c∈l+ f(x)>0⇒D<0f′′(x)=2a ⇒g(t)=2aat2+bt+c=2a2t2+2abt+2acg(0)=2ac=12⇒ac=6a=6,c=1a=1c=6a=3c=2a=2c=3⇒b2<24; b=1,2,3,4∴16 quadratic are possible