Let fx=sgncot-1x+tanπ2x, where [x] is the where [x] is the greatest integer function less than or equal to x. Then which of the following alternatives is/are true?
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a
f (x) is many-one but not an even function
b
f(x) is a periodic function.
c
f(x) is a bounded function.
d
The graph of f(x) remains above the x-axis.
answer is A.
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Detailed Solution
fx=sgncot-1x+tanπ2xsgncot-1x is defined when cot-1x is defined, which is ∀x∈R.tanπ2x is defined whenπ2x≠2n+12π, Where n∈Z,or x≠2n+1 or x∉2n+1,2n+2.Hence, domain of fx is ∪n∈Z2n+1,2n+2Also, cot-1x>0∀x∈R. Then fx=1+tanπ2x=1∴ fx=1,x∈DfFrom the graph, f(x) is periodic with period 2.